Q: The terms in SOP are called ___________
Solution: The SOP is the sum of products. It consists of min terms often called the product terms. Similarly, POS consists of max terms.
Q: A sum of products expression is a product term (min term) or several min terms ANDed together.
Solution: The statement is partially correct. A sum of products expression is a product term (min term) or several min terms OR ed(i.e. added) together.
Q: Which of the following is an incorrect SOP expression?
Solution: The second expression is incorrect because it consists of two maxterms ANDed together. This makes it a POS or the product of sum expression. Other options are valid SOP expressions.
Q: The corresponding min term when x=0, y=0 and z=1.
Solution: The min term is obtained by taking the complement of the zero values and taking the term with value 1 as it is. Here, x=0,y=0 and z=1, then the min term is x’y’z.
Q: LSI stands for ___________
Solution: It stands for large scale integration. This is the abstraction level of the integrated circuits. It can also be small scale, medium, large or very large scale integration.
Q: Which operation is shown in the following expression: (X+Y’).(X+Z).(Z’+Y’)
Solution: The expression comprises of max terms. Also, the terms are ANDed together, therefore it is a POS term.
Q: The number of min terms for an expression comprising of 3 variables?
Solution: If any expression comprises of n variables, its corresponding min terms are given by 2n. Here, n=3 since there are 3 variables therefore, min terms=23=8.
Q: The number of cells in a K-map with n-variables.
Solution: K-map is nothing but Karnaugh map. SOP and POS expressions can be simplified using the K-map. The number of cells in case of n-variables=2n.
Q: The output of AND gates in the SOP expression is connected using the ________ gate.
Solution: Since the product terms or the min terms are added in an SOP expression. Therefore, the OR gate is used to connect the AND gates.
Q: The expression A+BC is the reduced form of ______________
Solution: The second option is correct. It can simplified as follows: (A+B)(A+C) =AA+AC+AB+BC =A+AC+AB+BC =A(1+C)+AB+BC =A+AB+BC =A(1+B)+BC =A+BC.
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